
(877) 245-6972
(877) 245-6972
If you are looking for an affordable licensed traffic school online for California on the list, One Day Traffic School has been licensed by the courts and DMV for over 15 years and can be found on the CA DMV licensed traffic violators list. We offer the best online traffic school for the State of California. With more than 400,000 satisfied customers, One Day Traffic School has a created a quick and easy method for one to complete traffic school in less than a day. Our state of the art training methods make taking traffic school easy and convenient. We made traffic school flexibe to fit your need. You take our course from home or on the go. We make it work around your schedule.
If your certificate due date is quickly approaching and you need to complete the course as soon as possible, or TODAY, we got your back. Our quick easy service makes traffic school easy, and in addition we offer a speedy list of express packages. Once you completed we will send your certificate of completion electronically to the DMV/Court that very same day.
We offer a free to try traffic school course! Use our START NOW PAY LATER option and work on test sections for free. Make payment only before taking the final exam.
Reach us live chat, email or give us a call. We will gladly help you with all your CA DMV list of traffic school related questions.
"1-7 I would give a 10."
Melinda C. - Santa Barbara, California
"very easy and fast just like the hook of this website said. thanks"
Miguel A. - Los Angeles, California
"It was a ton of reading, but written in a fun, conversational style."
Jeanne O. - Ventura, California
"Thanks!"
Dora B. - Los Angeles, California
"Course was thorough and informative. The reading material was interesting and thought provoking."
Christopher D. - Orange, California
"In PART VI: DEFENSIVE DRIVING, Section 2: Avoiding Problems on the Road, Stopping Distances, Braking distance, there is a statement "For cars, if we use the CVC 26454 requirement that passenger vehicles be able to stop from a speed of 20 miles per hour in 25 feet, we can compute that at 55 miles per hour, it would take the same vehicle about 70 feet to stop." For a given gravitational acceleration g and a given coefficient of friction mu somewhere between 0 and the maximum coefficient of static friction mu_s, (initial speed)^2=2*mu*g*d_s where d_b is the braking distance. How do you reconcile the fact that 55^2/70 differs substantially from 20^2/25? "
Suguru A. - San Francisco, California
"I will highly recommend this online course to other drivers if needed."
Renika W. - San Bernardino, California
"It was so easy to do these courses "
Lisandro R. - Stanislaus, California
"I don't recall being asked if I have all the correct information before proceeding and completing the registration. It would be best to have a check your input before finalizing the registration. I worry that I may have indicated my Citation Number incorrectly. Other than that, the site and the course work/presentation is clear."
Ebert R. - Los Angeles, California
"The writer is hilarious and very informative, makes reading fun and enjoyable. Excellent!!"
Kristen T. - Orange, California